Integrand size = 19, antiderivative size = 227 \[ \int (a+b x)^{5/2} (c+d x)^{3/2} \, dx=\frac {3 (b c-a d)^4 \sqrt {a+b x} \sqrt {c+d x}}{128 b^2 d^3}-\frac {(b c-a d)^3 (a+b x)^{3/2} \sqrt {c+d x}}{64 b^2 d^2}+\frac {(b c-a d)^2 (a+b x)^{5/2} \sqrt {c+d x}}{80 b^2 d}+\frac {3 (b c-a d) (a+b x)^{7/2} \sqrt {c+d x}}{40 b^2}+\frac {(a+b x)^{7/2} (c+d x)^{3/2}}{5 b}-\frac {3 (b c-a d)^5 \text {arctanh}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )}{128 b^{5/2} d^{7/2}} \]
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Time = 0.09 (sec) , antiderivative size = 227, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.211, Rules used = {52, 65, 223, 212} \[ \int (a+b x)^{5/2} (c+d x)^{3/2} \, dx=-\frac {3 (b c-a d)^5 \text {arctanh}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )}{128 b^{5/2} d^{7/2}}+\frac {3 \sqrt {a+b x} \sqrt {c+d x} (b c-a d)^4}{128 b^2 d^3}-\frac {(a+b x)^{3/2} \sqrt {c+d x} (b c-a d)^3}{64 b^2 d^2}+\frac {(a+b x)^{5/2} \sqrt {c+d x} (b c-a d)^2}{80 b^2 d}+\frac {3 (a+b x)^{7/2} \sqrt {c+d x} (b c-a d)}{40 b^2}+\frac {(a+b x)^{7/2} (c+d x)^{3/2}}{5 b} \]
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Rule 52
Rule 65
Rule 212
Rule 223
Rubi steps \begin{align*} \text {integral}& = \frac {(a+b x)^{7/2} (c+d x)^{3/2}}{5 b}+\frac {(3 (b c-a d)) \int (a+b x)^{5/2} \sqrt {c+d x} \, dx}{10 b} \\ & = \frac {3 (b c-a d) (a+b x)^{7/2} \sqrt {c+d x}}{40 b^2}+\frac {(a+b x)^{7/2} (c+d x)^{3/2}}{5 b}+\frac {\left (3 (b c-a d)^2\right ) \int \frac {(a+b x)^{5/2}}{\sqrt {c+d x}} \, dx}{80 b^2} \\ & = \frac {(b c-a d)^2 (a+b x)^{5/2} \sqrt {c+d x}}{80 b^2 d}+\frac {3 (b c-a d) (a+b x)^{7/2} \sqrt {c+d x}}{40 b^2}+\frac {(a+b x)^{7/2} (c+d x)^{3/2}}{5 b}-\frac {(b c-a d)^3 \int \frac {(a+b x)^{3/2}}{\sqrt {c+d x}} \, dx}{32 b^2 d} \\ & = -\frac {(b c-a d)^3 (a+b x)^{3/2} \sqrt {c+d x}}{64 b^2 d^2}+\frac {(b c-a d)^2 (a+b x)^{5/2} \sqrt {c+d x}}{80 b^2 d}+\frac {3 (b c-a d) (a+b x)^{7/2} \sqrt {c+d x}}{40 b^2}+\frac {(a+b x)^{7/2} (c+d x)^{3/2}}{5 b}+\frac {\left (3 (b c-a d)^4\right ) \int \frac {\sqrt {a+b x}}{\sqrt {c+d x}} \, dx}{128 b^2 d^2} \\ & = \frac {3 (b c-a d)^4 \sqrt {a+b x} \sqrt {c+d x}}{128 b^2 d^3}-\frac {(b c-a d)^3 (a+b x)^{3/2} \sqrt {c+d x}}{64 b^2 d^2}+\frac {(b c-a d)^2 (a+b x)^{5/2} \sqrt {c+d x}}{80 b^2 d}+\frac {3 (b c-a d) (a+b x)^{7/2} \sqrt {c+d x}}{40 b^2}+\frac {(a+b x)^{7/2} (c+d x)^{3/2}}{5 b}-\frac {\left (3 (b c-a d)^5\right ) \int \frac {1}{\sqrt {a+b x} \sqrt {c+d x}} \, dx}{256 b^2 d^3} \\ & = \frac {3 (b c-a d)^4 \sqrt {a+b x} \sqrt {c+d x}}{128 b^2 d^3}-\frac {(b c-a d)^3 (a+b x)^{3/2} \sqrt {c+d x}}{64 b^2 d^2}+\frac {(b c-a d)^2 (a+b x)^{5/2} \sqrt {c+d x}}{80 b^2 d}+\frac {3 (b c-a d) (a+b x)^{7/2} \sqrt {c+d x}}{40 b^2}+\frac {(a+b x)^{7/2} (c+d x)^{3/2}}{5 b}-\frac {\left (3 (b c-a d)^5\right ) \text {Subst}\left (\int \frac {1}{\sqrt {c-\frac {a d}{b}+\frac {d x^2}{b}}} \, dx,x,\sqrt {a+b x}\right )}{128 b^3 d^3} \\ & = \frac {3 (b c-a d)^4 \sqrt {a+b x} \sqrt {c+d x}}{128 b^2 d^3}-\frac {(b c-a d)^3 (a+b x)^{3/2} \sqrt {c+d x}}{64 b^2 d^2}+\frac {(b c-a d)^2 (a+b x)^{5/2} \sqrt {c+d x}}{80 b^2 d}+\frac {3 (b c-a d) (a+b x)^{7/2} \sqrt {c+d x}}{40 b^2}+\frac {(a+b x)^{7/2} (c+d x)^{3/2}}{5 b}-\frac {\left (3 (b c-a d)^5\right ) \text {Subst}\left (\int \frac {1}{1-\frac {d x^2}{b}} \, dx,x,\frac {\sqrt {a+b x}}{\sqrt {c+d x}}\right )}{128 b^3 d^3} \\ & = \frac {3 (b c-a d)^4 \sqrt {a+b x} \sqrt {c+d x}}{128 b^2 d^3}-\frac {(b c-a d)^3 (a+b x)^{3/2} \sqrt {c+d x}}{64 b^2 d^2}+\frac {(b c-a d)^2 (a+b x)^{5/2} \sqrt {c+d x}}{80 b^2 d}+\frac {3 (b c-a d) (a+b x)^{7/2} \sqrt {c+d x}}{40 b^2}+\frac {(a+b x)^{7/2} (c+d x)^{3/2}}{5 b}-\frac {3 (b c-a d)^5 \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )}{128 b^{5/2} d^{7/2}} \\ \end{align*}
Time = 0.41 (sec) , antiderivative size = 220, normalized size of antiderivative = 0.97 \[ \int (a+b x)^{5/2} (c+d x)^{3/2} \, dx=\frac {\sqrt {a+b x} \sqrt {c+d x} \left (-15 a^4 d^4+10 a^3 b d^3 (7 c+d x)+2 a^2 b^2 d^2 \left (64 c^2+233 c d x+124 d^2 x^2\right )+2 a b^3 d \left (-35 c^3+23 c^2 d x+256 c d^2 x^2+168 d^3 x^3\right )+b^4 \left (15 c^4-10 c^3 d x+8 c^2 d^2 x^2+176 c d^3 x^3+128 d^4 x^4\right )\right )}{640 b^2 d^3}-\frac {3 (b c-a d)^5 \text {arctanh}\left (\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {d} \sqrt {a+b x}}\right )}{128 b^{5/2} d^{7/2}} \]
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Time = 0.26 (sec) , antiderivative size = 239, normalized size of antiderivative = 1.05
method | result | size |
default | \(\frac {\left (b x +a \right )^{\frac {5}{2}} \left (d x +c \right )^{\frac {5}{2}}}{5 d}-\frac {\left (-a d +b c \right ) \left (\frac {\left (b x +a \right )^{\frac {3}{2}} \left (d x +c \right )^{\frac {5}{2}}}{4 d}-\frac {3 \left (-a d +b c \right ) \left (\frac {\sqrt {b x +a}\, \left (d x +c \right )^{\frac {5}{2}}}{3 d}-\frac {\left (-a d +b c \right ) \left (\frac {\left (d x +c \right )^{\frac {3}{2}} \sqrt {b x +a}}{2 b}-\frac {3 \left (a d -b c \right ) \left (\frac {\sqrt {b x +a}\, \sqrt {d x +c}}{b}-\frac {\left (a d -b c \right ) \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \ln \left (\frac {\frac {1}{2} a d +\frac {1}{2} b c +b d x}{\sqrt {b d}}+\sqrt {b d \,x^{2}+\left (a d +b c \right ) x +a c}\right )}{2 b \sqrt {d x +c}\, \sqrt {b x +a}\, \sqrt {b d}}\right )}{4 b}\right )}{6 d}\right )}{8 d}\right )}{2 d}\) | \(239\) |
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Time = 0.27 (sec) , antiderivative size = 702, normalized size of antiderivative = 3.09 \[ \int (a+b x)^{5/2} (c+d x)^{3/2} \, dx=\left [-\frac {15 \, {\left (b^{5} c^{5} - 5 \, a b^{4} c^{4} d + 10 \, a^{2} b^{3} c^{3} d^{2} - 10 \, a^{3} b^{2} c^{2} d^{3} + 5 \, a^{4} b c d^{4} - a^{5} d^{5}\right )} \sqrt {b d} \log \left (8 \, b^{2} d^{2} x^{2} + b^{2} c^{2} + 6 \, a b c d + a^{2} d^{2} + 4 \, {\left (2 \, b d x + b c + a d\right )} \sqrt {b d} \sqrt {b x + a} \sqrt {d x + c} + 8 \, {\left (b^{2} c d + a b d^{2}\right )} x\right ) - 4 \, {\left (128 \, b^{5} d^{5} x^{4} + 15 \, b^{5} c^{4} d - 70 \, a b^{4} c^{3} d^{2} + 128 \, a^{2} b^{3} c^{2} d^{3} + 70 \, a^{3} b^{2} c d^{4} - 15 \, a^{4} b d^{5} + 16 \, {\left (11 \, b^{5} c d^{4} + 21 \, a b^{4} d^{5}\right )} x^{3} + 8 \, {\left (b^{5} c^{2} d^{3} + 64 \, a b^{4} c d^{4} + 31 \, a^{2} b^{3} d^{5}\right )} x^{2} - 2 \, {\left (5 \, b^{5} c^{3} d^{2} - 23 \, a b^{4} c^{2} d^{3} - 233 \, a^{2} b^{3} c d^{4} - 5 \, a^{3} b^{2} d^{5}\right )} x\right )} \sqrt {b x + a} \sqrt {d x + c}}{2560 \, b^{3} d^{4}}, \frac {15 \, {\left (b^{5} c^{5} - 5 \, a b^{4} c^{4} d + 10 \, a^{2} b^{3} c^{3} d^{2} - 10 \, a^{3} b^{2} c^{2} d^{3} + 5 \, a^{4} b c d^{4} - a^{5} d^{5}\right )} \sqrt {-b d} \arctan \left (\frac {{\left (2 \, b d x + b c + a d\right )} \sqrt {-b d} \sqrt {b x + a} \sqrt {d x + c}}{2 \, {\left (b^{2} d^{2} x^{2} + a b c d + {\left (b^{2} c d + a b d^{2}\right )} x\right )}}\right ) + 2 \, {\left (128 \, b^{5} d^{5} x^{4} + 15 \, b^{5} c^{4} d - 70 \, a b^{4} c^{3} d^{2} + 128 \, a^{2} b^{3} c^{2} d^{3} + 70 \, a^{3} b^{2} c d^{4} - 15 \, a^{4} b d^{5} + 16 \, {\left (11 \, b^{5} c d^{4} + 21 \, a b^{4} d^{5}\right )} x^{3} + 8 \, {\left (b^{5} c^{2} d^{3} + 64 \, a b^{4} c d^{4} + 31 \, a^{2} b^{3} d^{5}\right )} x^{2} - 2 \, {\left (5 \, b^{5} c^{3} d^{2} - 23 \, a b^{4} c^{2} d^{3} - 233 \, a^{2} b^{3} c d^{4} - 5 \, a^{3} b^{2} d^{5}\right )} x\right )} \sqrt {b x + a} \sqrt {d x + c}}{1280 \, b^{3} d^{4}}\right ] \]
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\[ \int (a+b x)^{5/2} (c+d x)^{3/2} \, dx=\int \left (a + b x\right )^{\frac {5}{2}} \left (c + d x\right )^{\frac {3}{2}}\, dx \]
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Exception generated. \[ \int (a+b x)^{5/2} (c+d x)^{3/2} \, dx=\text {Exception raised: ValueError} \]
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Leaf count of result is larger than twice the leaf count of optimal. 1740 vs. \(2 (183) = 366\).
Time = 0.55 (sec) , antiderivative size = 1740, normalized size of antiderivative = 7.67 \[ \int (a+b x)^{5/2} (c+d x)^{3/2} \, dx=\text {Too large to display} \]
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Timed out. \[ \int (a+b x)^{5/2} (c+d x)^{3/2} \, dx=\int {\left (a+b\,x\right )}^{5/2}\,{\left (c+d\,x\right )}^{3/2} \,d x \]
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